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-0.2x^2+5.2x+24=0
a = -0.2; b = 5.2; c = +24;
Δ = b2-4ac
Δ = 5.22-4·(-0.2)·24
Δ = 46.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.2)-\sqrt{46.24}}{2*-0.2}=\frac{-5.2-\sqrt{46.24}}{-0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.2)+\sqrt{46.24}}{2*-0.2}=\frac{-5.2+\sqrt{46.24}}{-0.4} $
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